So shouldn't dividing the pie by nothing result in the pie? Shouldn't one divided by zero equal one?
I mathematics, dividing by zero is disallowed because it supposedly would cause a logical conflict. Is this really true?
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Maybe this will helpDividing something by one means you take something and split it into one whole group. So if you have a pie and divide that pie by one, you are really just taking that pie and keeping it in its whole form of only one piece.42% Voted for by cosmosis, Weydon, TeChNoWC.
When you divide by 0, you are basically saying "I'm going to take this object and break it off into zero (aka nonexistent) groups." But you can't take a pie and split it off into nothing, that wouldn't make any sense.
This is why dividing anything by 0 is considered to be "undefined." You can't take a number, which represents a quantity, and just obliterate it. -
1/1=1If you have a pie, and divide it by 1, you don't get 2 pieces. You get one, whole pie, that you never cut.28% Voted for by Weydon, softball19girl32.





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Molzahn
June 29
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riddle me this
under that logic, how does X^0 equal one?7^3 is like saying 7*7*7
7^0 is like saying _____
there is no referenced number, and automatically it equals one?
The reason dividing by zero is undefined (like in an asymptote) is because the answer can be any and every number all at once. What about dividing an absence of quantity (zero) and 'obliterating' it? If I don't write down a number, can I assume it's one?
cosmosis
June 30
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My explanation for why dividing by 0 doesn't work still stands. It's logically impossible, which is why it's undefined.
As for 7^0, this page might help: http://mathforum.org/dr.math/faq/faq.number.to.0power.html
Molzahn
July 2
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f(x) = 7(x-1)/(x-1)
if you remove the constant, you have to put a restriction on when the variable equals zero.
f(x) = 7
(X =/= 1)
Now, my beef with this mathematical philosophy is that we are unaware of exactly how many constant variables contribute to the final equation, so we can't know exactly how many restrictions exist within equations. like any equation in physics e.g. e=mc^2 could possess countless restrictions that we could be unaware of. Are these realistic? no, just mathematical.
I think dividing out constants should always equal one, I haven't seen any reason why this would pose a practical problem.
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